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Which orbital hybridization maximizes diamond crystal lattice stiffness?

A)sp3 hybridization maintains tetrahedral geometry
B)sp hybridization allows linear arrangement
C)sp2 hybridization creates trigonal planar bonds
D)sd3 hybridization is geometrically complex

💡 Explanation

sp3 hybridization maximizes stiffness because it promotes strong sigma bonding in a tetrahedral configuration throughout the carbon lattice via electron repulsion minimizing angular strain. Therefore, sp3 bonds support equal distribution of forces rather than planar orientations sp/sp2.

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