Which outcome reduces conductivity when doping NaCl with CaO?

💡 Explanation

Adding CaO introduces Ca²⁺ substituting Na⁺, Charge neutrality requires vacancies, increasing the Schottky defect concentration as the favored *defect formation*. This reduces the availability of Na⁺ ions for ionic conduction because it creates charge imbalances therefore decreased flow rather than increased transport.

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