In a simulation of the Towers of Hanoi with 'n' disks, what happens to the number of moves required as the simulation hits the base case (n=1)?

💡 Explanation

The base case (n=1) in the Towers of Hanoi recursion directly solves the problem with a single move because only the smallest disk needs to be moved to its destination. Therefore, the required moves equal one, rather than exponentially increasing or following a different reduction pattern.

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