Which thermodynamic limit constrains the maximum efficiency of a Carnot engine operating with finite time intervals?

💡 Explanation

When operating with finite time intervals, a Carnot engine experiences irreversible losses, which limits its maximum possible efficiency to the Curzon-Ahlborn efficiency due to entropy generation reducing power output. Therefore, Curzon-Ahlborn efficiency results, rather than other relations dealing with phase equilibrium or particle distribution.

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